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From the rate expression for the following reactions, determine their order of reaction and dimensions of the rate constants. `a. 3NO(g) rarr N_(2)O(g),` Rate`=k[NO]^(2)` `b. H_(2)O_(2)(aq)+3I^(-)(aq)+2H^(o+) rarr 2H_(2)O(l)+I_(3)^(-),` Rate`=k[H_(2)O_(2)][I^(-)]` `c. CH_(3)CHO(g)rarr CH_(4)(g)+CO(g),` Rate`=k[CH_(3)CHO]^(3//2)` `d. C_(2)H_(5)Cl(g) rarr C_(2)H_(4)(g)+HCl(g),` Rate `k[C_(2)H_(5)Cl]` |
Answer» (i) Given rate = `k[NO]^(2)` Therefore , order of the reaction = 2 `k = ("Rate")/([NO]^(2))` Dimension f = `( "mol" L^(-1) s^(-1))/(( "mol" L^(-1))^(2))` = `("mol" L^(-1) s^(-1))/( mol^(2) L^(-2))` = `L mol^(-1) s^(-1)` (ii) Given that = `k [H_(2)O_(2)][l^(-)]` Therefore , order of the reaction = 2 `k = ("Rate")/([H_(2)O_(2)][I^(-)])` Dimension of = `( "mol" L^(-1) s^(-1))/(("mol" L^(-1)) ("mol" L^(-1)))` = `L mol^(-1) s^(-1)` Given rate = `k[CH_(3)CHO]^(3//2)` Therefore , order of reaction = `(3)/(2)` `k = ( "Rate")/([CH_(3)CHO]^(3/2))` Dimension of `( "mol" L^(-1) s^(-1))/(("mol" L^(-1))^((3)/(2)))` = `("mol" L^(-1) s^(-1))/( mol^((3)/(2)) L^((3)/(2)))` = `L^((1)/(2)) mol^((1)/(2)) s^(-1)` (iv) Given rate = k `[C_(2)H_(5)Cl]` Therefore , order of the reaction = 1 `k = ("Rate")/([C_(2)H_(5)Cl])` Dimension of `= ( "mol" L^(-1)s^(-1))/( "mol" L^(-1))` =` s^(-1)` |
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