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from the relation R=R_0A^(1//3), where R_0 is a constant and A is the mass number of a nucleus, show that the nuclear matter density is nearly constant (i.e., independent of A ). |
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Answer» SOLUTION :Nuclear MATTER density =`("Mass of nucleus")/("Volume of nucleus")` `=(mA)/(4/3piR^3) =(mA)/(4/3 piR_0^3A)` `=m/(4/3piR_0^3)=2.3 xx 10^(17) kg //m^3` = constant |
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