From the sum of 2y2 + 3yz, -y2 - y2 – 22 and yz + 2z2, subtract the

1.	From the sum of 2y2 + 3yz, -y2 - y2 – 22 and yz + 2z2, subtract the sum of3y2– 22 and - y2 +y2 +22 pls answer
Answer» Answer: 4YZ - 22 + 2z^2 - 3y^2 Step-by-step EXPLANATION: (2y^2 + 3YZ - y^2 - y^2 - 22 + YZ + 2z^2)-(3y^2 -22 - y^2 + y^2 + 22) = 2y^2 + 3yz - y^2 - y^2 - 22 + yz + 2z^2 - 3y^2 + 22 + y^2 - y^2 - 22 = 4yz - 22 + 2z^2 - 3y^2

From the sum of 2y2 + 3yz, -y2 - y2 – 22 and yz + 2z2, subtract the sum of3y2– 22 and - y2 +y2 +22 pls answer

Answer»

Answer:

4YZ - 22 + 2z^2 - 3y^2

Step-by-step EXPLANATION:

(2y^2 + 3YZ - y^2 - y^2 - 22 + YZ + 2z^2)-(3y^2 -22 - y^2 + y^2 + 22)

= 2y^2 + 3yz - y^2 - y^2 - 22 + yz + 2z^2 - 3y^2 + 22 + y^2 - y^2 - 22

= 4yz - 22 + 2z^2 - 3y^2