1.

From the two e.m.f. equations e_1 = E_0 sin (100 pit) and e_2 = E_0 sin (100 pit + pi/3), we find that

Answer»

`e_1` leads `e_2` by `60^@`
`e_2` lags behind `e_1` by `60^@`
`e_2` ACHIEVES its maximum VALUE `1/300` SECOND before `e_1`
`e_1` achieves its maximum value `1/300` second before `e_2`

Answer :C


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