1.

From the Zener diode circuit shown in figure, the current through the Zener diode is

Answer»

34 mA
31.5 mA
36.5 mA
2.5 mA

Solution :Here, `R_(L )=20xx10^(3)Omega, V_(i)=220 V,`
Zener voltage, `V_(Z )=50V`
LOAD current,
`I_(L )=(V_(Z ))/(R_(L ))=(50)/(20xx10^(3))`
`=2.5XX10^(-3)A`
Current through R,
`I=(220-50)/(5xx10^(3))=34xx10^(-3)A`
Zener current, `I_(Z)=I-I_(L)=34xx10^(-3)-2.5xx10^(-3)=31.5mA`


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