1.

Fructose reduces Tollen's reagent due to

Answer»

asymmetric carbons
PRIMARY alcoholic group
secondary alcoholic group
enolisation of FRUCTOSE followed by conversion to aldehyde by base

SOLUTION :Fructose is a ketone. In PRESENCE of a base. It is converted into a mixture of glucose and mannose (Lobry de Bruyn van Ekenstein rearrangement via enolisation followed by conversion to aldehyde as SHOWN on both of which contain the `-CHO` group and hence reduce Tollens' reagent to give silver mirror test. Thus , option (d) , is correct.


Discussion

No Comment Found

Related InterviewSolutions