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`gamma_(A)` of liquid is `7//8` of `gamma_(R)` of liquid. `alpha_(g)` is vessel isA. `(gamma_(R))/(8)`B. `(gamma_(R))/(12)`C. `(gamma_(R))/(24)`D. `(gamma_(R))/(36)` |
Answer» Correct Answer - C `gamma_(A) = (7)/(8)gammaR` and `gamma_(A) = gamma_(R) - 3alpha` |
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