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Gas at a pressure `P_(0)` in contained as a vessel. If the masses of all the molecules are halved and their speeds are doubles. The resulting pressure P will be equal toA. `4 P_(0)`B. `2 P_(0)`C. `P_(0)`D. `P_(0)//2` |
Answer» Correct Answer - B `P=1/3 (mN)/(V) v_(rms)^(2) :. P prop mv_(rms)^(2)` so `(P_2)/(P_1) = (m_2)/(m_1) xx ((v_2)/(v_1))^(2) = (m_(1)//2)/(m_1)((2v_(1))/(v_1))^(2) = 2` `implies P_(2) = 2P_(1) = 2P_(0)`. |
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