Gas with in a chamber, passes through the cycle shown in (figure). Determine the net heat added to the system during process AB is `Q_(AB)= 20J`. No heat is transferred during process BC and net work done during the cycle is `15J`

Gas with in a chamber, passes through the cycle shown in (figure). Det

1.	Gas with in a chamber, passes through the cycle shown in (figure). Determine the net heat added to the system during process AB is `Q_(AB)= 20J`. No heat is transferred during process BC and net work done during the cycle is `15J`
Answer» According to first law of thermodynamics. In process CA, `dQ_(CA)=dU_(CA)+dW_(CA)` In process AB `dQ_(AB)=dU_(AB)+dW_(AB)`, and In process BC `dQ_(BC)=dU_(BC)+dW_(BC)` Adding the three equations, we get `dQ_(CA)+dQ_(AB)+dQ_(BC)= (dU_(CA)+dU_(AB)+dU_(BC))` `+(dW_(CA)+dW_(AB)+dW_(BC)`....(i) As the process is cyclic, `dU=dU_(CA)+dU_(AB)+dU_(BC)=0` From (i) `dQ_(CA)+20+0=0+15` `dQ_(CA)=15-20= -5J` This is the net heat added to the system.

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