InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Gaseous hydrogen contained initially under standard conditions in sealed vessel of volume `V = 5 L` was cooled by `Delta T = 55 K`. Find how much the internal energy of the gas will change and what amount of heat will be lost by the gas. |
|
Answer» By the first law of thermodynamics `Delta Q = Delta U + Delta W` Here `Delta W = =` as the volume remains constant. `:. Delta Q = Delta U` Now `Delta U = (m)/(M) (R ) C_(V) (- Delta T)` `= - (m)/(M) (R )/(gamma - 1) Delta T` `(as C_(V) = (R )/(gamma - 1))` We have `P_(0)V = (m)/(M) RT_(0)` `= - (1.013 xx 10^(5) xx (5 xx 10^(-3)) xx 55)/(273 (1.4 - 1)) = - 255 J` |
|