Saved Bookmarks
| 1. |
Ge and Si diode conduct at 0.3 V and 0.7respectively. In the following figure if Ge diode connection is reversed, the value of V_0 changes by |
|
Answer» 0.2 V Equivalent VOLTAGE DROP cross the combination Ge and Si diode = 0.3 V `implies ` Current `i=(12-0.3)/(5kOmega)=2.34mA` `:.` Output voltage `V_0 =Ri = 5kOmega xx 2.34 mA = 11.7V` Now consider the case when diode connection are REVERSED. In this case voltage drop across the diode.s combination = 0.7 V `implies ` Current `i=(12-0.7)/(5kOmega) = 2.26mA` `:. V_0=iR=2.26mA xx5kOmega =11.3 V` HENCE CHARGE in the value of `V_0=11.7-11.3 = 0.4V` |
|