1.

Ge(II) compounds are powerful reducing agents whereas Pb(IV) compounds are strong oxidants. It is because

Answer»

Pb is more electropositive than Ge
Ionization potential of lead is less than that of Ge
Ionic RADII of `Pb^(2+) and Pb^(4+)` are larger than those of `Ge^(2+) and Ge^(4+)`
of more pronounced inert pair EFFECT in lead than in Ge

Solution :Ge(II) tends to acquire Ge(IV) state by loss of electrons. Hence it is REDUCING in nature. Pb(IV) tends to acquire Pb(II) O.S by grain electrons. Hence it is oxidising in nature. This is due to inert pair effect.


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