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Answer» Case 1: numbers with 3 are like 3,13,23,......,303 they are in AP with a=3, d=10 let the total number of pages with the DIGIT 3 be N. 303 = 3 + (n-1)10 ⇒ n-1 = 300/10 = 30 ⇒ n = 31 number of pages = 31
case 2: number like 30,31,...39; 130,131,...139; 230,231,...239 from 30 to 39 - there are 10 numbers from 130 to 139 - there are 10 numbers from 230 to 239 - there are 10 numbers total = 10+10+10 = 30
but we have already counted 33,133 and 233. so number of pages = 30-3 = 27
case 3: the number 300,301 and 302. (303 has already been counted) so numbers = 3
So total number of pages = 31+27+3 = 61
every number having three has only one three except 33,133,233 and 303. number of pages with 2 threes = 4 number of pages with only one three = 61 - 4 = 57
total number of PRINTING of 3 = 57×1 +4×2 = 57+8 = 65.
So the digit 3 has been printed 65 times and number of pages with only one 3 present is 57.
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