1.

Gift Find the points on the curve 4x2 +9y2 = 1 where the tangents are perpendicular to the line 2y + x = 0​

Answer»

4x^2+9y^2=1{2x+3y}^2=12x^2+3y^2+2.2x.3y=12x^2+3y^2+12xy=12y+x=02y= -xy=-x÷2



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