1.

Give A^(@)(1/3 Al^(3+))=63 Omega^(-1) cm^(2) mol^(-1) and Lambda^(@)(1/2 SO_(4)^(2)) = 80 Omega^(-1). The value ofLambda^(oo)Al_(2)(SO_4)_3 would be

Answer»

`143 OMEGA^(-1) CM^(2) mol^(-1)`
`206 Omega^(-1) cm^(2) mol^(-1)`
`286 Omega^(-1) cm^(2) mol^(-1)`
`858 Omega^(-1) cm^(2) mol^(-1)`

Solution :`Lambda^(@)""_((Al^3+)=Lambda^(@)""_((1/3Al^(3+)))`
`=3 XX 63 =189 Omega^(-1) cm^(2) mol^(-1)Lambda^(@)""_((SO_4^(2-)))=2Lambda^(@)""_((1/2SO_(4)^(2-)))`
`=2 xx 80 =160 Omega^(-1) cm^(2) mol^(-1) =858 Omega^(-1) cm^2 mol^(-1)`


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