1.

Give and explain reducing behaviour of sulphur dioxide.

Answer»

Solution :As Sulphur dioxide can readily be oxidised, it acts as a reducing agent. It reduces CHLORINE into hydrochloric acid.
`SO_(2)+2H_(2)O+Cl_(2)rarr H_(2)SO_(4)+2HCl`
It also reduces potassium permanganate and dichromate to `Mn^(2+) and CR^(3+)` respectively.
`2KMnO_(4)+5SO_(2)+2H_(2)Orarr K_(2)SO_(4)+2MnSO_(4)+2H_(2)SO_(4)`
`K_(2)Cr_(2)O_(7)+3SO_(2)+H_(2)SO_(4)rarr K_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+H_(2)O`


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