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Give cel reaction, expression and formula for copper - Silver galvanic cell. |
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Answer» SOLUTION :COPPER - Silver cell redox reaction: `Cu_((S))+2Ag_((aq))^(+) to 2Ag_((S))+Cu_((aq))^(2+)`. .(i) Half-cell reaction of galvanic cell is as follows: Cathode (reduction) : `2Ag_((aq))^(2+)+2e^(-)toAg_((S))`. . (ii) Anode (oxidation) : `Cu_((S))toCu_((aq))^(2+)+2e^(-)`. . . (iii) So, the sum of reaction (ii) and (iii) is a TOTAL reaction (i). According to the reaction, silver electrode acts as a cathode and copper electrode acts as an anode. the cell can be represented as: `Cu_((S))|Cu_((aq))^(2+)||Ag_((aq))^(+)|Ag_((S))` and we have `E_(cell)=E_(right)-E_("left")=E_(Ag^(+)|Ag)-E_(Cu^(2+)|Cu)` |
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