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Give Nerst equation to calculate electrode potential for any concentration of ions for the following electrochemical cell. |
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Answer» Solution :`Ni(s)|Ni^(2+)(aq)|AG(aq)|Ag^(+)`. The cell reaction is `Ni+2Ag^(+)(aq) to Ni^(2+) (aq)+2Ag` `E_("cell")=E_("cell")^(0)-(2.303RT)/(NF)LOG""([Ni^(2+)])/([Ag^(+)]^(2))` |
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