1.

Give plausible explanation for each of the following (i) Cyclohexanone forms cyanohydrin in good yield but 2, 2, 6-trimethylcyclohexanone does not. (ii) There are two - NH_3, groups in semicarbazide. However, only one is involved in the formation of semicarbazones. (iii) During the preparation of esters from a carboxylic acid and an alcohol in the presence of an acid catalyst, the water or the ester should be removed as soon as it is formed

Answer»

Solution :(i)
Nucleophilic attack by the `CN^(-)` ion does not occur in reaction II due to steric hindrance. There is no such steric hindrance in cyclohexanone, therefore, nucleophilic attack by the `CN^-` ion occurs readily and hence cyclohexanone cyanohydrin is obtained in good yield.
(ii)
Lone pair of electrons on the -NH, group ATTACHED directly to carbonyl group is involved in resonance as SHOWN above. As a result, electron density on this NH group decreases and hence it does not act as a nucleophile. However, the lone pair of electrons on the other NH group (ie, attached to NH) is not involved in resonance and hence is available for nucleophilic attack on the C =0 group.
(III) The formation of esters from a carboxylic acid and an alcohol in presence of an acid catalyst is a reversible reaction.
`underset("Carboxylic acid")(RCOOH) + underset("Alcohol")(ROH) overset(H_(2)SO_(4)) To shift the EQUILIBRIUM in the forward direction, the water or the ester formed should be removed as fast as it is formed.


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