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| 1. |
Give reason for the following : All five bonds in PCl_5 molecule are not equivalent. |
| Answer» Solution : `dsp^(3)` hybridisation of orbital takes place in `PCl_5`GIVING rise to trigonal bipyramidal shape. All the BONDS are not in same PLANE. Axial bonds are longer than equatorial bonds due to more repulsion in the former. | |