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Give reason : n-Butyl bromide has higher boiling point than t-butyl bromide. |
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Answer» SOLUTION :`underset("n-Butyl BROMIDE")(CH_(3) - CH_(2) - CH_(2) - CH_(2)- Br ) "" underset("t-Butyl bromide") (CH_(3) - underset(CH_(3))underset(|)overset(CH_(3))overset(|)C - Br ) ` n-Butyl bromide has a greater surface AREA and hence greater van der Waals forces between the molecules. Hence it boils at a higher temperature than l-butyl bromide. |
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