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Give reasons for the following : (i) (CH_(3))_(3)P=O exists but (CH_(3))_(3)N=O does not. (ii) Oxygen has less electron gain enthalpy with negative sign than sulphur. (iii) H_(3)PO_(2) is a stronger reducing agent than H_(3)PO_(3). |
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Answer» Solution :(i) As N can.t form 5 covalent bonds/its maximum covalency is FOUR. (II) This is due to very small SIZE of oxygen atom/repulsion between electrons is large in relatively small 2p sub - shell. (iii) In `H_(3)PO_(2)` there are `2P-H` bonds, whereas in `H_(3)PO_(3)` there is 1 `P-H` bond. |
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