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Give reasons for the following : (i) Mn^(3+) is a good oxidising agent. (ii) E_(M^(2+)//M)^(@) values are not regular for first row transition metals (3d series ). (iii) Although 'F' is more electronegative than 'O', the highest fluoride of Mn is MnF_(4) while thehighest oxide is Mn_(2)O_(7). |
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Answer» Solution :(i) `Mn^(3+)` is a good oxidising agent because `E_(Mn^(3+)//Mn^(2+))^(@)` isvery high(+1.57 V). As a result , `Mn^(3+)` ion can be easily reduced `Mn^(2+)` ion by accepting an electron. Therefore , it is a good oxidising agent. (ii) It is DUE to ther reason that the variation in the vlues of enthalpy of atomisation and enthalpy of HYDRATION for `M^(2+)` IONS are not aquite regular. (iii) It is PROBABLY due to the reason that the elementoxygen can form multiple bonds with the transition metals but fluorine cannot do so. As a result , the ELEMENT Mn exbibits +4 oxidation sate in `MnF_(4)` and +7 oxidation sate is `Mn_(2)O_(7)`
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