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Give reasons : (i) SO_(2) is reducing while TeO_(2) is an oxidizing agent. (ii) Nitrogen does not form pentahalide. (iii) Icl is more reactive than I_(2). |
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Answer» Solution :(i) + 6 OXIDATION stateof S is more stable than+4. Hence, `SO_(2)` act as reducing agent. Since stabilityof +6 oxidation decreases from S to TE. Hence, reducing character of dioxide decreases while oxidising character increases. Thus, `TeO_(2)` acts as an oxidising agent. (ii) Nitrogen does not form Pentahalides due to the absence of empty d-orbital. (iii) ICl is more reactive than `I_(2)` because the over lapping of orbitals of two dissimilar ATOMS is less EFFECTIVE than the OVERLAPPING of orbitals of similar atoms. Hence, I-Cl bond is weaker and more reactive. |
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