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Give SI unit of magnetic field from Biot-Savart law. |
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Answer» Solution :According to Biot-Savart LAW, `dB=mu_(0)/(4pi)Idl(SINTHETA)/r^(2)` `dB=((T*m)/A)((A*m)/m^(2))` = T (TESLA) If we take I = I A, dl = 1 m, r = 1 m and `theta=90^(@)`, then `dB=mu_(0)/(4pi)=(4pixx10^(-7))/(4pi)=10^(-7)` tesla `therefore` 1 tesla = `10^(7)` dB Thus, one tesla is `10^(7)` times the magnetic field produced by a CONDUCTING wire of length one meter and carrying current of one AMPERE at a distance of one meter from it and perpendicular to it. |
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