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Give that the standard electrode potentials (E^@) of metals are: K^+//K=-2.93V, Ag^+//Ag=0.80V,Cu^(2+)//Cu=0.34 V, Mg^(+2)//Mg=-2.37V, Cr^(3+)//Cr=-0.74V, Fe^(2+)//Fe=-0.44V Arrange these metals in an increasing order of their reducing power. |
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Answer» Solution :More NEGATIVE REDUCTION potential values more is reducing power. `Ag^+//Alt Cu^(2+)//Cu LT FE^(2+)//Fe lt Cr^(3+) //Cr lt Mg^(2+)//Mg lt K^+//K` |
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