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Give the decreasing order of (o+p)/(m) ratio of the reactions or decreasingorder of the reactivitygiven is problem 11.11. |
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Answer» <P> Solution :Reactivity order of `SE` reactiion or `((o+p)/(m))` ratio (same explanation as in Problem `11.10`)`o-, p-` DIRECTING reactivity and `((o+p)/(m))` ratio order. i.`underset((VIII))(-NH-)overset(O)overset(||)(C-) underset(gt)(gt) underset((I))(-R) (-CHMe_(2) underset(gt)(gt) underset((II))(-CMe_(3))) underset(gt)(gt) underset((VII))(-Ar) underset(gt)(gt) underset((III))(I)` ii. `m-` directing reactivity order: `underset((V))(-CX_(3)) underset(gt)(gt) underset((VI))(-C) -= N underset(gt)(gt) underset((IV)) overset(O)overset(||)(-C-O-R)` But `((o+p)/(m))` ratio order of compounds in Problem 11.11 is: `underset((VIII))(O) underset(gt)(gt) underset((I))(A) underset(gt)(gt) underset((II))(C) underset(gt)(gt) underset((VII))(M) underset(gt)(gt) underset((III))(E) underset(gt)(gt) underset((IV))(G) underset(gt)(gt) underset((VI))(K) underset(gt)(gt) underset((V))(I)` |
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