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Give the disproportionation reaction of H_3PO_3. |
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Answer» Solution :`H_3PO_3` on HEATING undergoes self-oxidation reduction, i.e., disproportionation to form `PH_3` in which is reduced and `H_3PO_4` in which P is oxidised. Oxidation states of P in `H_3PO_3` , `PH_3 and H_3PO_4` are +3, -3 and +5, RESPECTIVELY. `UNDERSET("PHOSPHOROUS acid ")overset(+3)(4H_3PO_3) overset(Delta)to underset("Phosphine")overset(-3)(PH_3) + underset("Orthophosphoric acid ") overset(+5)(3H_3PO_4)` |
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