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Give the espression for the magnetic induction due tobar magnet on the equitorial line ? |
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Answer» Solution :MAGNETIC inductionon the equatorial LINE of a bar MAGNET is , `B= (mu_0)/(4pi) (M)/((d^(2) + l^(2))^(3//2))` In case of SHORT bar magnet the magnetic INDUCTION on the equatorail line is , `B = (mu_0)/(4pi)(M)/(d^(3))` |
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