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Give the espression for the magnetic induction due tobar magnet on aixal line ? |
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Answer» Solution :Magnetic induction on the AXIAL line of a BAR magnet , is ` B = (mu_0)/( 4PI) (2Md)/((d^(2) -l^(2))^(2))` In case of shortbar magnet the magnetic INDCUTION on the axial line is `B=(mu_0)/(4pi) (2M)/(d^(3))` . |
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