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Give the oxidation and reduction half cell reaction taking place in the Daniel cell. |
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Answer» Solution :Zinc is oxidised to `Zn^(2+)` ions and the `Cu^(2+)` ions are reduced to metallic COPER. The half reactions are represented as below. `""Zn_((s)) RARR Zn_((AQ))^(2+)+2e^-)" (OXIDATION)"` Loss of election oxidation `Cu_((aq))^(2+)+2e^(-) rarr Cu_((s))" (reduction)"` Gain of electron oxidation. |
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