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Give the relation between electric field and electric potential . |
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Answer» Solution :Consider a positive charge q kept FIXED at the origin. To move a unit positive charge by a SMALL distance dx in the electric FIELD E, the work done is GIVEN by dW = -E dx. The minus sign IMPLIES that work is done against the electric field. This work done is equal to electric potential difference. Therefore, dW=dV(or)dV=-Edx Hence E=`-(dV)/(dx)` The electric field is the negative gradient of the electric potential. |
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