1.

Give the relationship between the equivalent weight and molecular weight of KMnO_(4) in ( a) acidic (b) alkaline and (c ) neutral media.

Answer»

Solution :(a) `E = M //5` (b) In STRONGLY ALKALINE medium, `E= M` . In WEAKLY alkaline medium `E= M//3`(c ) `E = M//3`. Refer to page.


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