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Give the structure of the compound, C(C_(4)H_(8)) which when treated with H_(2)O//H_(2)SO_(4) gives C_(4)H_(10)O which cannot be resolved into optical isomers. |
Answer» Solution :SINCE alkene `C(C_(4)H_(8))` on treatment with `H_(2)O//H_(2)SO_(4)` gives an alcohol `C_(4)H_(10)O`, which cannot be resolved, therefore, the alkene must be 2-methylpropene  The other two POSSIBLE alkenes having M.F. `C_(4)H_(8)` are 1-butene adn 2-butene. these upon HYDRATION will give 2-butanol which is opticaly active. `underset("1-Butanol")(CH_(3)CH_(2)CH=CH_(2)) underset(H_(2)SO_(4))overset(H_(2)O)to underset("2-Butanol (OPTICALLY active)")(CH_(3)CH_(2)-underset(OH)underset(|)overset(**)(C)H-CH_(3)) underset(H_(2)SO_(4))overset(H_(2)O)larr underset("2-Butene")(CH_(3)CH=CHCH_(3))` |
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