1.

Given 1. C("graphite")+O_(2)(g) to CO_(2)(g), DeltaH^(@)=-3935 kJ mol^(-1) 2. H_(2)(g)+(1)/(2)O_(2)(g) to H_(2)O(l),DeltaH^(@)=-285 kJ mol^(-1) 3. CO_(2)(g)+2H_(2)O(l) to CH_(4)(g)+2O_(2)(g),DeltaH^(@)=+890.3kJ mol^(-1) Based on the above thermochemical equations the value of Delta(r)H^(@) at 298 K for the reaction C("graphite")+2H_(2)(g) to CH_(4)(g) will be

Answer»

`+78.8 KJ MOL^(-1)`
`+144.0 kJ mol^(-1)`
`-74.8 kJ mol^(-1)`
`-1440 kJ mol^(-1)`

Solution :APPLY inspection METHOD : `eq.1+(2xxeq.2)+eq.3`


Discussion

No Comment Found