1.

Given 2Fe_(2)O_(3)(s) to 4Fe(s)+3O_(2)(g),DeltaG^(@)=-1487 "kJ mol"^(-1) 2CO(g)+O_(2)(g) to 2CO_(2)(g),DeltaG^(@)=-514.4"kJ mol"^(-1) Free energy change DeltaG^(@) for the reaction 2Fe_(2)O_(3)(s)+6CO(g) to 4Fe(s)+6CO_(2)(g) will be

Answer»

`-168.2 "KJ MOL"^(-1)`
`-208.0 "kJ mol^(-1)`
`56.2 "kJ mol^(-1)`
`-112.4 "kJ mol^(-1)`

SOLUTION :Cal. `DELTAG^(@) FOLLOWING [eqn. (i) +3 eqn. (ii)`


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