1.

Given, 2Fe+(3)/(2)O_(2)toFe_(2)O_(3),DeltaH=-193.4kJ,Mg+(1)/(2)O_(2)to MgO,DeltaH=-140.2kJ What is the DeltaH for the following reaction? 3Mg+Fe_(2)O_(3) to 3MgO+2Fe

Answer»

`-227.2kJ`
`-272.3kJ`
`227.2kJ`
`272.3kJ`

Solution :`2FE+(3)/(2)O_(2)toFe_(2)O_(3),DeltaH=-193.4kJ`. . (i)
`Mg+(1)/(2)O_(2)toMgO,DeltaH=-140.2kJ`. ..(ii)
On multiplying Eq. (iI) by (3) and subtracting eq. (i) we GET the FINAL equation,
`3Mg+Fe_(2)O_(3)to2Fe+3MgO,`
`therefore DeltaH=(-420.6)+(193.4)=-227.2kJ`


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