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Given;A and B are parallel to the ground.C crosses A and B.C crosses A at an angle of 150°.So, considering the corresponding angles C crosses B at an angle of 150°.[Since, correspondent angles are equal]For reference, check the image at the attachment. 2, 6 are the required correspondent angles.Therefore, considering the alternate angles, the third archer launched arrow C at 30°.In the image at the attachment, the alternate angles are 1 and 7. Launching the arrow on the tree, angle 7 will be angle of launch. |
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