1.

Given below are the half-cell reactions ltbr Mn^(2+)+2e^(-)toMn,E^(@)=-1.18V 2(Mn^(3+)+e^(-)toMn^(2+)),E^(@)=+1.51V The E^(@) for 3Mn^(2+)toMn+2Mn^(3+) will be:

Answer»

`-2.69V`, the reaction will not occur
`-2.69V`, the reaction will occur
`-0.33V`, the reaction will not occur
`-0.33V`, the reaction will occur

Solution :`Mn^(2+)OVERSET(E_(1)^(0)+1.51V)toMn^(2+)overset(E_(2)^(0)=-1.18V)toMn`
`therefore` For `Mn^(2+)` disproportionation, `E^(o)=-1.51V-1.18V`
`=-2.69V LT 0`
Reaction is non-spontaneous.


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