1.

Given below are the half cell reactions: Mn^(2+)+2e^(-)toMn,""E^(@)=-1.18V 2(Mn^(3+)+e^(-)toMn^(2+)),E^(@)=+1.51V The E^(@) the 3Mn^(2+)toMn+2Mn^(3+) will be

Answer»

`-0.33V`, the reaction will occur
`-2.69V`, the reaction will not occur
`-2.69V`, the reaction will occur
`-0.33V`, the reaction will not occur

Solution :The GIVEN cell reaction can be obtained from half-cell reactions as under:
`MN^(2+)+2e^(-)toMn,E^(@)=-1.18V`
`underline(""2MN^(2+)to2Mn^(3+)+2e^(-),E^(@)=-1.51V)`
OVERALL reaction:
`3Mn^(2+)toMn+2Mn^(3+),E^(@)=-1.18V+(-1.51)`
`=-2.69V`
As `E_(cell)^(@)` is -ve, reaction will not occur.


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