1.

Given below are the standard electrode potentials of few half-cells. The correct order of these metals in increasing reducing power will be K^(+)//K=-2.93 V , Ag^+ /Ag=0.80 V, Mg^(2+)/Mg=-2.37 V, Cr^(3+)/Cr =-0.74 V

Answer»

K lt MG lt Cr lt AG
Ag lt Cr lt Mg lt K
Mg lt K lt Cr lt Ag
Cr lt Ag lt Mg lt K

SOLUTION :Higher the oxidation potential, more easily it is oxidised and hence greater is the REDUCING power. Hence, increasing ORDER of reducing power is Ag lt Cr lt Mg ltK


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