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Given de- Broglie's explanation of quantisation of angular momentum as proposed by Bohr. |
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Answer» Solution :For an electron MOVING in `n^(th)` drcular orbit of radius `r_(n)`, the TOTAL distanceis `=2pir_(n)` Circumference of a stationary Bohr orbit of radius `r_(n)` is EQUAL to integral multiple of wavelength of matter waves `2pir_(n)=nlamda""......(i)` The de-broglie wavelength of the electron moving in the `n^(th)` orbit. `lamda=(H)/(mv)""......(2)` From equation (1) and (2), `2pir_(n)=(nh)/(mv)` i.e., `mvr_(n)=(nh)/(2pi)` But, angular momentum of the electron is `L=mvr_(n)` Hence `L=(nh)/(2pi)` |
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