Given DeltaH_("oxidation") (HCN) = 45.2 kJ "mole"^(-1) & DeltaH_("oxid – InterviewSolution

1.	Given DeltaH_("oxidation") (HCN) = 45.2 kJ "mole"^(-1) & DeltaH_("oxidation") (CH_(3)CO_(2)H) = 2.1 kJ "mole"^(-1), which of the following statement is correct?
Answer» `pKa(HCN) =pKa(CH_(3)CO_(2)H)` `pKa(HCN) GT pKa(CH_(3)CO_(2)H)` `pKa(HCN) lt pKa(CH_(3)CO_(2)H)` `pKa(HCN) = (45.17)/(2.07) pKa(CH_(3)CO_(2)H)` ANSWER :B

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