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Given E = 40xyi + 20x^2j + 2k. Calculate the potential between two points (1,-1,0) and (2,1,3).(a) 105(b) 106(c) 107(d) 108The question was asked in unit test.My question is from Electric Potential in section Electrostatic Fields of Electromagnetic Theory

Answer»

The correct answer is (b) 106

For explanation: V = -∫ E.dl = -∫ (40xy dx + 20x^2 dy + 2 dz), from (2,1,3) to (1,-1,0), we get Vpq on integrating from Q to P. Vpq = 106 volts.



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