1.

Given E_(Cr^(3+)//Cr)^(@)=-0.74V E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51V E_(CrO_(7)^(2-)//Cr^(3+))^(@)=1.33,E_(Cl//Cl^(-))^(@)=1.36V Based on the data given above, strongest oxidizng agent will be

Answer»

`MnO_(4)^(-)`
`Cl^(-)`
`Cr^(3+)`
`MN^(2+)`

Solution :Higher the REDUCTION potential, more easily it is REDUCED and hence stronger is the oxidizing agent. As reduction potential of `MnO_(4)^(-)//Mn^(2)` is MAXIMUM, hence it is strongest oxidizing agent.


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