1.

Given: E_(Zn^(+2)//Zn)^(@) =- 0.76V E_(Cu^(+2)//Cu)^(@) = +0.34V K_(f)[Cu(NH_(3))_(4)]^(2+) = 4 xx 10^(11) (2.303R)/(F) = 2 xx 10^(-4) When 1 mole of NH_(3) added to cathode compartement than emf of cell is (at 298K):

Answer»

`0.81 V`
`1.91 V`
`1.1V`
`0.72`

ANSWER :C


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