Given electrode potentials are:Fe^(3+) +e rarrFe^(2+) ,E^@=0.771V I_2 – InterviewSolution

1.	Given electrode potentials are:Fe^(3+) +e rarrFe^(2+) ,E^@=0.771V I_2 +2e rarr 2I^- ,E^@=0.536V E^@ cell for the cell reaction, 2Fe^(3+) +2I^- rarr2Fe(2+) +I_2is:
Answer» `(2xx0.7710.536)=1.006V` `(0.771 -0.5xx0.536)=0.503V` `0.771-0.536=0.235 V` `0.536-0.771=-0.236 V` ANSWER :A

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