1.

Given electrode potentials are , Fe^(3+) + e to Fe^(2+), E^@ = 0.771V"" I_2 + 2e to 2I^(-), E^@ = 0.536 V, E^@ cell for the cell reaction, 2Fe^(3+) + 2I^(-) to 2Fe^(2+) + I_2 is

Answer»

`0.536 - 0.771 = - 0.236 V`
`(0.771 - 0.5 XX 0.536) = 0.503 V`
`0.771- 5.36 = 0.235V`
`(2 xx 0.771 - 0.536) = 1.006V`

ANSWER :C


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