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Given figure is the part of some circuit. Charge on the capacitor in the circuit is given by q=3(3-e^(-1)), (coulomb) where t is time in seconds. Let V_(A), V_(B) and V_(C) be the potentials of points A, B and C, respectively. At t=0 if V_(A)=5 V and a constant current i_(0)=1 Amp flows through R=1Omega, then find the V_(P) (in volt) |
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Answer» SOLUTION :`i=i_(0)+(DQ)/(DT)` `=1+3e^(-t)`
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