1.

Given , for `Sn^(+4) // Sn^(2+)` , standard reduction potential is `0.15` V and for `Au^(3+)//Au` , standard reduction potential is 1.5 V. For the reaction , `3Sn^(2+) + 2 Au^(3+) to 3 Sn^(4+) + 2 Au , ` the value of `E_("cell")^(@)` is ,A. `+1.35`B. `+2.55`C. `-1.35`D. `-2.55`

Answer» Correct Answer - A
`E_("cell")^(@) = E_("cathode")^(@) - E_("anode")^(@)`
= `1.5 - 0.15 = 1.35 V`


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